What are the solutions to the equation x^2-x-35=-x+1 ?

The solutions to the equation x^2-x-35=-x+1 are x=6,x=-6

Find the zeros of x^2-x-35=-x+1

The zeros of x^2-x-35=-x+1 are x=6,x=-6

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x^{2} - x - 35 = - x + 1

x = 6, x = - 6

Solution steps

x^{2} - x - 35 = - x + 1

Move

35

to the right side

x^{2} - x = - x + 36

Move

x

to the left side

x^{2} = 36

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 36, x = - 36

36 = 6

- 36 = - 6

x = 6, x = - 6

4 x^{2} - 16 x - 33

x^{2} - 2 x - 24 = 0

y, x y - 3 x + 4 x^{2} = 7

y, x^{2} - x y + y^{2} = 7

4 (x + 1)^{2} - 7 = 45

What are the solutions to the equation x^2-x-35=-x+1 ?
The solutions to the equation x^2-x-35=-x+1 are x=6,x=-6
Find the zeros of x^2-x-35=-x+1
The zeros of x^2-x-35=-x+1 are x=6,x=-6