What are the solutions to the equation x^2+20x=-172 ?

The solutions to the equation x^2+20x=-172 are x=-10+6sqrt(2)i,x=-10-6sqrt(2)i

Find the zeros of x^2+20x=-172

The zeros of x^2+20x=-172 are x=-10+6sqrt(2)i,x=-10-6sqrt(2)i

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x^{2} + 20 x = - 172

x = - 10 + 62 i, x = - 10 - 62 i

Solution steps

x^{2} + 20 x = - 172

Move

172

to the left side

x^{2} + 20 x + 172 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot 172}{2 \cdot 1}

Simplify

2 0^{2} - 4 \cdot 1 \cdot 172 : 122 i

x_{1, 2} = \frac{- 20 \pm 12 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 20 + 12 2 i}{2 \cdot 1}, x_{2} = \frac{- 20 - 12 2 i}{2 \cdot 1}

x = \frac{- 20 + 12 2 i}{2 \cdot 1} : - 10 + 62 i

x = \frac{- 20 - 12 2 i}{2 \cdot 1} : - 10 - 62 i

The solutions to the quadratic equation are:

x = - 10 + 62 i, x = - 10 - 62 i

9 x^{2} = 54 x

x^{2} - 2 x - 1

2 x^{2} + 54 = - 24 x

(x - 4) (x - 3) + 2 = x - 1

\frac{x ^{2} - 1}{6} - \frac{x - 1}{4} = 3

What are the solutions to the equation x^2+20x=-172 ?
The solutions to the equation x^2+20x=-172 are x=-10+6sqrt(2)i,x=-10-6sqrt(2)i
Find the zeros of x^2+20x=-172
The zeros of x^2+20x=-172 are x=-10+6sqrt(2)i,x=-10-6sqrt(2)i