What are the solutions to the equation 2(x+9)^2-29=33 ?

The solutions to the equation 2(x+9)^2-29=33 are x=sqrt(31)-9,x=-sqrt(31)-9

Find the zeros of 2(x+9)^2-29=33

The zeros of 2(x+9)^2-29=33 are x=sqrt(31)-9,x=-sqrt(31)-9

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2 (x + 9)^{2} - 29 = 33

x = 31 - 9, x = - 31 - 9

Decimal Notation

x = - 3.43223 \dots, x = - 14.56776 \dots

Solution steps

2 (x + 9)^{2} - 29 = 33

Move

29

to the right side

2 (x + 9)^{2} = 62

Divide both sides by

2

(x + 9)^{2} = 31

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 9 = 31 : x = 31 - 9

Solve

x + 9 = - 31 : x = - 31 - 9

The solutions to the quadratic equation are:

x = 31 - 9, x = - 31 - 9

x^{2} - 5 x + \frac{5}{4} = 0

4 x^{2} + 57 = - 28 x

t^{2} = - 16

y, x^{3} - 3 x^{2} y + y^{2} = 1

(x - 5)^{2} = 25

What are the solutions to the equation 2(x+9)^2-29=33 ?
The solutions to the equation 2(x+9)^2-29=33 are x=sqrt(31)-9,x=-sqrt(31)-9
Find the zeros of 2(x+9)^2-29=33
The zeros of 2(x+9)^2-29=33 are x=sqrt(31)-9,x=-sqrt(31)-9