What are the solutions to the equation 9^2+11^2=x^2 ?

The solutions to the equation 9^2+11^2=x^2 are x=sqrt(202),x=-sqrt(202)

Find the zeros of 9^2+11^2=x^2

The zeros of 9^2+11^2=x^2 are x=sqrt(202),x=-sqrt(202)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

9^{2} + 1 1^{2} = x^{2}

x = 202, x = - 202

Decimal Notation

x = 14.21267 \dots, x = - 14.21267 \dots

Solution steps

9^{2} + 1 1^{2} = x^{2}

Switch sides

x^{2} = 9^{2} + 1 1^{2}

Simplify

9^{2} + 1 1^{2} : 202

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 202, x = - 202

3 x^{2} - 3 x - 6 = 0

2 x + 1 = 5 x + 1 - 3 x

∣ 2 x + 5 ∣ = 3

∣ x ∣ + 5 \geq 11

3 c^{3} - 6 c^{2}

What are the solutions to the equation 9^2+11^2=x^2 ?
The solutions to the equation 9^2+11^2=x^2 are x=sqrt(202),x=-sqrt(202)
Find the zeros of 9^2+11^2=x^2
The zeros of 9^2+11^2=x^2 are x=sqrt(202),x=-sqrt(202)