What are the solutions to the equation 4z^2-4z-15=0 ?

The solutions to the equation 4z^2-4z-15=0 are z= 5/2 ,z=-3/2

Find the zeros of 4z^2-4z-15=0

The zeros of 4z^2-4z-15=0 are z= 5/2 ,z=-3/2

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4 z^{2} - 4 z - 15 = 0

z = \frac{5}{2}, z = - \frac{3}{2}

Decimal Notation

z = 2.5, z = - 1.5

Solution steps

4 z^{2} - 4 z - 15 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 ( - 15 )}{2 \cdot 4}

(- 4)^{2} - 4 \cdot 4 (- 15) = 16

z_{1, 2} = \frac{- ( - 4 ) \pm 16}{2 \cdot 4}

Separate the solutions

z_{1} = \frac{- ( - 4 ) + 16}{2 \cdot 4}, z_{2} = \frac{- ( - 4 ) - 16}{2 \cdot 4}

z = \frac{- ( - 4 ) + 16}{2 \cdot 4} : \frac{5}{2}

z = \frac{- ( - 4 ) - 16}{2 \cdot 4} : - \frac{3}{2}

The solutions to the quadratic equation are:

z = \frac{5}{2}, z = - \frac{3}{2}

x^{2} + 7 x = x

2 x^{2} + 4 = 8 x

s^{2} + 9

9 x^{2} = 6 x + 2

7 x = 7 - 3 x^{2}

What are the solutions to the equation 4z^2-4z-15=0 ?
The solutions to the equation 4z^2-4z-15=0 are z= 5/2 ,z=-3/2
Find the zeros of 4z^2-4z-15=0
The zeros of 4z^2-4z-15=0 are z= 5/2 ,z=-3/2