What are the solutions to the equation 9x^2+36x+40=0 ?

The solutions to the equation 9x^2+36x+40=0 are x=-2+i 2/3 ,x=-2-i 2/3

Find the zeros of 9x^2+36x+40=0

The zeros of 9x^2+36x+40=0 are x=-2+i 2/3 ,x=-2-i 2/3

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9 x^{2} + 36 x + 40 = 0

x = - 2 + i \frac{2}{3}, x = - 2 - i \frac{2}{3}

Solution steps

9 x^{2} + 36 x + 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 36 \pm 3 6 ^{2} - 4 \cdot 9 \cdot 40}{2 \cdot 9}

Simplify

3 6^{2} - 4 \cdot 9 \cdot 40 : 12 i

x_{1, 2} = \frac{- 36 \pm 12 i}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 36 + 12 i}{2 \cdot 9}, x_{2} = \frac{- 36 - 12 i}{2 \cdot 9}

x = \frac{- 36 + 12 i}{2 \cdot 9} : - 2 + i \frac{2}{3}

x = \frac{- 36 - 12 i}{2 \cdot 9} : - 2 - i \frac{2}{3}

The solutions to the quadratic equation are:

x = - 2 + i \frac{2}{3}, x = - 2 - i \frac{2}{3}

\frac{1}{2} x^{2} - 10 = \frac{3}{2} x^{2}

114.7 + 12.8 t - \frac{9.8 t ^{2}}{2} = 0

y^{2} = 15 y - 36

y, 2 x^{2} + 2 y^{2} - 2 x - 2 y + 9 = 0

5 (x^{2} - 8) - 9 = 6

What are the solutions to the equation 9x^2+36x+40=0 ?
The solutions to the equation 9x^2+36x+40=0 are x=-2+i 2/3 ,x=-2-i 2/3
Find the zeros of 9x^2+36x+40=0
The zeros of 9x^2+36x+40=0 are x=-2+i 2/3 ,x=-2-i 2/3