What are the solutions to the equation 4x^2+61=28x ?

The solutions to the equation 4x^2+61=28x are x= 7/2+sqrt(3)i,x= 7/2-sqrt(3)i

Find the zeros of 4x^2+61=28x

The zeros of 4x^2+61=28x are x= 7/2+sqrt(3)i,x= 7/2-sqrt(3)i

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4 x^{2} + 61 = 28 x

x = \frac{7}{2} + 3 i, x = \frac{7}{2} - 3 i

Solution steps

4 x^{2} + 61 = 28 x

Move

28 x

to the left side

4 x^{2} + 61 - 28 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 28 x + 61 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 28 ) \pm ( - 28 ) ^{2} - 4 \cdot 4 \cdot 61}{2 \cdot 4}

Simplify

(- 28)^{2} - 4 \cdot 4 \cdot 61 : 83 i

x_{1, 2} = \frac{- ( - 28 ) \pm 8 3 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 28 ) + 8 3 i}{2 \cdot 4}, x_{2} = \frac{- ( - 28 ) - 8 3 i}{2 \cdot 4}

x = \frac{- ( - 28 ) + 8 3 i}{2 \cdot 4} : \frac{7}{2} + 3 i

x = \frac{- ( - 28 ) - 8 3 i}{2 \cdot 4} : \frac{7}{2} - 3 i

The solutions to the quadratic equation are:

x = \frac{7}{2} + 3 i, x = \frac{7}{2} - 3 i

4 x^{2} + 69 = 36 x

6 (x - 3)^{2} - 6 = 0

y, x^{2} + 2 x y + y^{2} = 0

- 4 x^{2} - 24 x - 36 = 0

x^{2} - 109 = - 8 x

What are the solutions to the equation 4x^2+61=28x ?
The solutions to the equation 4x^2+61=28x are x= 7/2+sqrt(3)i,x= 7/2-sqrt(3)i
Find the zeros of 4x^2+61=28x
The zeros of 4x^2+61=28x are x= 7/2+sqrt(3)i,x= 7/2-sqrt(3)i