What are the solutions to the equation 5(x^2-4)-5=-5 ?

The solutions to the equation 5(x^2-4)-5=-5 are x=2,x=-2

Find the zeros of 5(x^2-4)-5=-5

The zeros of 5(x^2-4)-5=-5 are x=2,x=-2

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5 (x^{2} - 4) - 5 = - 5

x = 2, x = - 2

Solution steps

5 (x^{2} - 4) - 5 = - 5

Move

5

to the right side

5 (x^{2} - 4) = 0

Divide both sides by

5

x^{2} - 4 = 0

Move

4

to the right side

x^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 4, x = - 4

4 = 2

- 4 = - 2

x = 2, x = - 2

y, x^{2} y^{2} = 1

x^{2} + 2 x + a

x, x^{2} + y^{2} + z^{2} = 9

x^{2} + 12 x + 20 = 0

4 w^{2} = 4 w + 3

What are the solutions to the equation 5(x^2-4)-5=-5 ?
The solutions to the equation 5(x^2-4)-5=-5 are x=2,x=-2
Find the zeros of 5(x^2-4)-5=-5
The zeros of 5(x^2-4)-5=-5 are x=2,x=-2