What are the solutions to the equation roots x^2+x-6 ?

The solutions to the equation roots x^2+x-6 are x=2,x=-3

Find the zeros of roots x^2+x-6

The zeros of roots x^2+x-6 are x=2,x=-3

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roots

x^{2} + x - 6

x = 2, x = - 3

Solution steps

x^{2} + x - 6

The roots are the intercepts with the x-axis

(y = 0)

x^{2} + x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 6) = 5

x_{1, 2} = \frac{- 1 \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 5}{2 \cdot 1}, x_{2} = \frac{- 1 - 5}{2 \cdot 1}

x = \frac{- 1 + 5}{2 \cdot 1} : 2

x = \frac{- 1 - 5}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 2, x = - 3

4 (x^{2} - 6) - 3 = 9

4 x^{2} - 25 = 0

9 w^{2} + 6 w + 1 = - 18

d x^{2} = 3.6

13 x^{2} + 25 x + 25 = 0

What are the solutions to the equation roots x^2+x-6 ?
The solutions to the equation roots x^2+x-6 are x=2,x=-3
Find the zeros of roots x^2+x-6
The zeros of roots x^2+x-6 are x=2,x=-3