What are the solutions to the equation roots x^2+8x+17 ?

The solutions to the equation roots x^2+8x+17 are x=-4+i,x=-4-i

Find the zeros of roots x^2+8x+17

The zeros of roots x^2+8x+17 are x=-4+i,x=-4-i

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roots

x^{2} + 8 x + 17

x = - 4 + i, x = - 4 - i

Solution steps

x^{2} + 8 x + 17

The roots are the intercepts with the x-axis

(y = 0)

x^{2} + 8 x + 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 17}{2 \cdot 1}

Simplify

8^{2} - 4 \cdot 1 \cdot 17 : 2 i

x_{1, 2} = \frac{- 8 \pm 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 2 i}{2 \cdot 1}, x_{2} = \frac{- 8 - 2 i}{2 \cdot 1}

x = \frac{- 8 + 2 i}{2 \cdot 1} : - 4 + i

x = \frac{- 8 - 2 i}{2 \cdot 1} : - 4 - i

The solutions to the quadratic equation are:

x = - 4 + i, x = - 4 - i

0 = 30 + 3 t - \frac{9.8 t ^{2}}{2}

r^{2} - r + 49 = 0

x^{2} - 101 = - 1

2 v^{2} + 7 v + 5 = 0

x^{2} - 200 x - 7500 = 0

What are the solutions to the equation roots x^2+8x+17 ?
The solutions to the equation roots x^2+8x+17 are x=-4+i,x=-4-i
Find the zeros of roots x^2+8x+17
The zeros of roots x^2+8x+17 are x=-4+i,x=-4-i