What are the solutions to the equation 4x^2+20x=-17 ?

The solutions to the equation 4x^2+20x=-17 are x=(-5+2sqrt(2))/2 ,x=-(5+2sqrt(2))/2

Find the zeros of 4x^2+20x=-17

The zeros of 4x^2+20x=-17 are x=(-5+2sqrt(2))/2 ,x=-(5+2sqrt(2))/2

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4 x^{2} + 20 x = - 17

x = \frac{- 5 + 2 2}{2}, x = - \frac{5 + 2 2}{2}

Decimal Notation

x = - 1.08578 \dots, x = - 3.91421 \dots

Solution steps

4 x^{2} + 20 x = - 17

Move

17

to the left side

4 x^{2} + 20 x + 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 4 \cdot 17}{2 \cdot 4}

2 0^{2} - 4 \cdot 4 \cdot 17 = 82

x_{1, 2} = \frac{- 20 \pm 8 2}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 20 + 8 2}{2 \cdot 4}, x_{2} = \frac{- 20 - 8 2}{2 \cdot 4}

x = \frac{- 20 + 8 2}{2 \cdot 4} : \frac{- 5 + 2 2}{2}

x = \frac{- 20 - 8 2}{2 \cdot 4} : - \frac{5 + 2 2}{2}

The solutions to the quadratic equation are:

x = \frac{- 5 + 2 2}{2}, x = - \frac{5 + 2 2}{2}

x^{2} - b x + 16

y, y^{2} = - x^{2}

x^{2} - 60 = 4 x

- 6 x^{(2)} - 4 x + 2 = 0

lo g_{10} (4) (x^{2} - x + 2) = \frac{1}{2}

What are the solutions to the equation 4x^2+20x=-17 ?
The solutions to the equation 4x^2+20x=-17 are x=(-5+2sqrt(2))/2 ,x=-(5+2sqrt(2))/2
Find the zeros of 4x^2+20x=-17
The zeros of 4x^2+20x=-17 are x=(-5+2sqrt(2))/2 ,x=-(5+2sqrt(2))/2