What are the solutions to the equation roots x^2+6x+25 ?

The solutions to the equation roots x^2+6x+25 are x=-3+4i,x=-3-4i

Find the zeros of roots x^2+6x+25

The zeros of roots x^2+6x+25 are x=-3+4i,x=-3-4i

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roots

x^{2} + 6 x + 25

x = - 3 + 4 i, x = - 3 - 4 i

Solution steps

x^{2} + 6 x + 25

The roots are the intercepts with the x-axis

(y = 0)

x^{2} + 6 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

Simplify

6^{2} - 4 \cdot 1 \cdot 25 : 8 i

x_{1, 2} = \frac{- 6 \pm 8 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 8 i}{2 \cdot 1}, x_{2} = \frac{- 6 - 8 i}{2 \cdot 1}

x = \frac{- 6 + 8 i}{2 \cdot 1} : - 3 + 4 i

x = \frac{- 6 - 8 i}{2 \cdot 1} : - 3 - 4 i

The solutions to the quadratic equation are:

x = - 3 + 4 i, x = - 3 - 4 i

x^{2} + 4 x = 0

x (x - 3) + 2 x (x + 4) = 12

x^{2} - 8 x = - x

x^{2} + x - 16 = x

5 (x^{2} - 7) - 1 = 9

What are the solutions to the equation roots x^2+6x+25 ?
The solutions to the equation roots x^2+6x+25 are x=-3+4i,x=-3-4i
Find the zeros of roots x^2+6x+25
The zeros of roots x^2+6x+25 are x=-3+4i,x=-3-4i