What are the solutions to the equation 2x^2+12x-2=0 ?

The solutions to the equation 2x^2+12x-2=0 are x=-3+sqrt(10),x=-3-sqrt(10)

Find the zeros of 2x^2+12x-2=0

The zeros of 2x^2+12x-2=0 are x=-3+sqrt(10),x=-3-sqrt(10)

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2 x^{2} + 12 x - 2 = 0

x = - 3 + 10, x = - 3 - 10

Decimal Notation

x = 0.16227 \dots, x = - 6.16227 \dots

Solution steps

2 x^{2} + 12 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 2 ( - 2 )}{2 \cdot 2}

1 2^{2} - 4 \cdot 2 (- 2) = 410

x_{1, 2} = \frac{- 12 \pm 4 10}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 12 + 4 10}{2 \cdot 2}, x_{2} = \frac{- 12 - 4 10}{2 \cdot 2}

x = \frac{- 12 + 4 10}{2 \cdot 2} : - 3 + 10

x = \frac{- 12 - 4 10}{2 \cdot 2} : - 3 - 10

The solutions to the quadratic equation are:

x = - 3 + 10, x = - 3 - 10

t^{5} + t^{3}

(\frac{2}{7})^{1.4}

- 6 = \frac{r}{5} - 8

6 q - 8 \leq 3 q + 4

\frac{x}{3} = 7

What are the solutions to the equation 2x^2+12x-2=0 ?
The solutions to the equation 2x^2+12x-2=0 are x=-3+sqrt(10),x=-3-sqrt(10)
Find the zeros of 2x^2+12x-2=0
The zeros of 2x^2+12x-2=0 are x=-3+sqrt(10),x=-3-sqrt(10)