What are the solutions to the equation -4n^2-1=-4n ?

The solutions to the equation -4n^2-1=-4n are n= 1/2

Find the zeros of -4n^2-1=-4n

The zeros of -4n^2-1=-4n are n= 1/2

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- 4 n^{2} - 1 = - 4 n

n = \frac{1}{2}

Decimal Notation

n = 0.5

Solution steps

- 4 n^{2} - 1 = - 4 n

Move

4 n

to the left side

- 4 n^{2} - 1 + 4 n = 0

Write in the standard form

a x^{2} + b x + c = 0

- 4 n^{2} + 4 n - 1 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 4 ) ( - 1 )}{2 ( - 4 )}

4^{2} - 4 (- 4) (- 1) = 0

n_{1, 2} = \frac{- 4 \pm 0}{2 ( - 4 )}

n = \frac{- 4}{2 ( - 4 )}

\frac{- 4}{2 ( - 4 )} = \frac{1}{2}

n = \frac{1}{2}

The solution to the quadratic equation is:

n = \frac{1}{2}

2 x (6 - 5 x) = - 7

- 3 r^{2} - r - 10 = - 4 r^{2}

x^{2} + 10 x + 25 = 0

2 x^{2} + 4 = - 7 x

8 q^{2} - 26 q + 15 = 0

What are the solutions to the equation -4n^2-1=-4n ?
The solutions to the equation -4n^2-1=-4n are n= 1/2
Find the zeros of -4n^2-1=-4n
The zeros of -4n^2-1=-4n are n= 1/2