What are the solutions to the equation 4(5x+9)^2+34=38 ?

The solutions to the equation 4(5x+9)^2+34=38 are x=-8/5 ,x=-2

Find the zeros of 4(5x+9)^2+34=38

The zeros of 4(5x+9)^2+34=38 are x=-8/5 ,x=-2

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4 (5 x + 9)^{2} + 34 = 38

x = - \frac{8}{5}, x = - 2

Decimal Notation

x = - 1.6, x = - 2

Solution steps

4 (5 x + 9)^{2} + 34 = 38

Move

34

to the right side

4 (5 x + 9)^{2} = 4

Divide both sides by

4

(5 x + 9)^{2} = 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

5 x + 9 = 1 : x = - \frac{8}{5}

Solve

5 x + 9 = - 1 : x = - 2

The solutions to the quadratic equation are:

x = - \frac{8}{5}, x = - 2

2 x^{2} + 7 x + 3 = 12

x^{2} - 6 x = - 6 x + 4

5 (x + 6)^{2} - 34 = - 29

6 x^{2} = 3 x + 3

x, x^{2} + 2 y^{2} = k^{2}

What are the solutions to the equation 4(5x+9)^2+34=38 ?
The solutions to the equation 4(5x+9)^2+34=38 are x=-8/5 ,x=-2
Find the zeros of 4(5x+9)^2+34=38
The zeros of 4(5x+9)^2+34=38 are x=-8/5 ,x=-2