What are the solutions to the equation 0.5x^2-7x=-5x ?

The solutions to the equation 0.5x^2-7x=-5x are x=4,x=0

Find the zeros of 0.5x^2-7x=-5x

The zeros of 0.5x^2-7x=-5x are x=4,x=0

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0.5 x^{2} - 7 x = - 5 x

x = 4, x = 0

Solution steps

0.5 x^{2} - 7 x = - 5 x

Multiply both sides by

10

5 x^{2} - 70 x = - 50 x

Move

50 x

to the left side

5 x^{2} - 20 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 5 \cdot 0}{2 \cdot 5}

(- 20)^{2} - 4 \cdot 5 \cdot 0 = 20

x_{1, 2} = \frac{- ( - 20 ) \pm 20}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 20}{2 \cdot 5}, x_{2} = \frac{- ( - 20 ) - 20}{2 \cdot 5}

x = \frac{- ( - 20 ) + 20}{2 \cdot 5} : 4

x = \frac{- ( - 20 ) - 20}{2 \cdot 5} : 0

The solutions to the quadratic equation are:

x = 4, x = 0

5 c^{2} - 21 c + 11 = - 4 c

- x^{2} + 160 x - 900 = 0

3 x^{2} + a x = a^{2}

7 x^{2} - 3 = - 11

4 (x^{2} - 5) + 5 = - 3

What are the solutions to the equation 0.5x^2-7x=-5x ?
The solutions to the equation 0.5x^2-7x=-5x are x=4,x=0
Find the zeros of 0.5x^2-7x=-5x
The zeros of 0.5x^2-7x=-5x are x=4,x=0