What are the solutions to the equation a^2+6a-26=0 ?

The solutions to the equation a^2+6a-26=0 are a=-3+sqrt(35),a=-3-sqrt(35)

Find the zeros of a^2+6a-26=0

The zeros of a^2+6a-26=0 are a=-3+sqrt(35),a=-3-sqrt(35)

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a^{2} + 6 a - 26 = 0

a = - 3 + 35, a = - 3 - 35

Decimal Notation

a = 2.91607 \dots, a = - 8.91607 \dots

Solution steps

a^{2} + 6 a - 26 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 26 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 26) = 235

a_{1, 2} = \frac{- 6 \pm 2 35}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- 6 + 2 35}{2 \cdot 1}, a_{2} = \frac{- 6 - 2 35}{2 \cdot 1}

a = \frac{- 6 + 2 35}{2 \cdot 1} : - 3 + 35

a = \frac{- 6 - 2 35}{2 \cdot 1} : - 3 - 35

The solutions to the quadratic equation are:

a = - 3 + 35, a = - 3 - 35

3 p^{2} - 4 = - 24

x^{2} - 8 x - 56 = 0

x^{2} - 5 x - 1 = - 1

7 x^{2} - 847 = 0

y^{2} + 4 y + 4 = 16

What are the solutions to the equation a^2+6a-26=0 ?
The solutions to the equation a^2+6a-26=0 are a=-3+sqrt(35),a=-3-sqrt(35)
Find the zeros of a^2+6a-26=0
The zeros of a^2+6a-26=0 are a=-3+sqrt(35),a=-3-sqrt(35)