What are the solutions to the equation 4x^2+36x=-77 ?

The solutions to the equation 4x^2+36x=-77 are x=-7/2 ,x=-11/2

Find the zeros of 4x^2+36x=-77

The zeros of 4x^2+36x=-77 are x=-7/2 ,x=-11/2

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4 x^{2} + 36 x = - 77

x = - \frac{7}{2}, x = - \frac{11}{2}

Decimal Notation

x = - 3.5, x = - 5.5

Solution steps

4 x^{2} + 36 x = - 77

Move

77

to the left side

4 x^{2} + 36 x + 77 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 36 \pm 3 6 ^{2} - 4 \cdot 4 \cdot 77}{2 \cdot 4}

3 6^{2} - 4 \cdot 4 \cdot 77 = 8

x_{1, 2} = \frac{- 36 \pm 8}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 36 + 8}{2 \cdot 4}, x_{2} = \frac{- 36 - 8}{2 \cdot 4}

x = \frac{- 36 + 8}{2 \cdot 4} : - \frac{7}{2}

x = \frac{- 36 - 8}{2 \cdot 4} : - \frac{11}{2}

The solutions to the quadratic equation are:

x = - \frac{7}{2}, x = - \frac{11}{2}

x, 0 = 3 m^{2} x^{2} + 2 m x - 5

4 (x + 7)^{2} = 16

5 (x - 3)^{2} = - 225

16 x^{2} - 24 x - 25 = 0

y, x^{2} + y^{2} + 4 x - 2 y + 5 = 0

What are the solutions to the equation 4x^2+36x=-77 ?
The solutions to the equation 4x^2+36x=-77 are x=-7/2 ,x=-11/2
Find the zeros of 4x^2+36x=-77
The zeros of 4x^2+36x=-77 are x=-7/2 ,x=-11/2