What are the solutions to the equation (-x-5)(2x+4)=0 ?

The solutions to the equation (-x-5)(2x+4)=0 are x=-5,x=-2

Find the zeros of (-x-5)(2x+4)=0

The zeros of (-x-5)(2x+4)=0 are x=-5,x=-2

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(- x - 5) (2 x + 4) = 0

x = - 5, x = - 2

Solution steps

(- x - 5) (2 x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

- x - 5 = 0 or 2 x + 4 = 0

Solve

- x - 5 = 0 : x = - 5

Solve

2 x + 4 = 0 : x = - 2

The solutions to the quadratic equation are:

x = - 5, x = - 2

x^{2} - \frac{1}{3} x - 2 = 0

(x + 25)^{2} + 7 = 0

x^{2} - 3 x = 0

2 x^{2} - 11 = - 47

5 (x - 9)^{2} = 720

What are the solutions to the equation (-x-5)(2x+4)=0 ?
The solutions to the equation (-x-5)(2x+4)=0 are x=-5,x=-2
Find the zeros of (-x-5)(2x+4)=0
The zeros of (-x-5)(2x+4)=0 are x=-5,x=-2