What are the solutions to the equation -5m^2+12m+8=3-5m ?

The solutions to the equation -5m^2+12m+8=3-5m are m=-(-17+sqrt(389))/(10),m=(17+sqrt(389))/(10)

Find the zeros of -5m^2+12m+8=3-5m

The zeros of -5m^2+12m+8=3-5m are m=-(-17+sqrt(389))/(10),m=(17+sqrt(389))/(10)

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- 5 m^{2} + 12 m + 8 = 3 - 5 m

m = - \frac{- 17 + 389}{10}, m = \frac{17 + 389}{10}

Decimal Notation

m = - 0.27230 \dots, m = 3.67230 \dots

Solution steps

- 5 m^{2} + 12 m + 8 = 3 - 5 m

Move

5 m

to the left side

- 5 m^{2} + 17 m + 8 = 3

Move

3

to the left side

- 5 m^{2} + 17 m + 5 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 ( - 5 ) \cdot 5}{2 ( - 5 )}

1 7^{2} - 4 (- 5) \cdot 5 = 389

m_{1, 2} = \frac{- 17 \pm 389}{2 ( - 5 )}

Separate the solutions

m_{1} = \frac{- 17 + 389}{2 ( - 5 )}, m_{2} = \frac{- 17 - 389}{2 ( - 5 )}

m = \frac{- 17 + 389}{2 ( - 5 )} : - \frac{- 17 + 389}{10}

m = \frac{- 17 - 389}{2 ( - 5 )} : \frac{17 + 389}{10}

The solutions to the quadratic equation are:

m = - \frac{- 17 + 389}{10}, m = \frac{17 + 389}{10}

x^{2} - 4 x = - 5 x

z (z - 3) = 5

6 x^{2} - 21 = - 5 x

5 n^{2} - 30 n + 20 = - n

- 34 = 15 - 80 x^{2}

What are the solutions to the equation -5m^2+12m+8=3-5m ?
The solutions to the equation -5m^2+12m+8=3-5m are m=-(-17+sqrt(389))/(10),m=(17+sqrt(389))/(10)
Find the zeros of -5m^2+12m+8=3-5m
The zeros of -5m^2+12m+8=3-5m are m=-(-17+sqrt(389))/(10),m=(17+sqrt(389))/(10)