What are the solutions to the equation 3x^2+228=54x ?

The solutions to the equation 3x^2+228=54x are x=9+sqrt(5),x=9-sqrt(5)

Find the zeros of 3x^2+228=54x

The zeros of 3x^2+228=54x are x=9+sqrt(5),x=9-sqrt(5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} + 228 = 54 x

x = 9 + 5, x = 9 - 5

Decimal Notation

x = 11.23606 \dots, x = 6.76393 \dots

Solution steps

3 x^{2} + 228 = 54 x

Move

54 x

to the left side

3 x^{2} + 228 - 54 x = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} - 54 x + 228 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 54 ) \pm ( - 54 ) ^{2} - 4 \cdot 3 \cdot 228}{2 \cdot 3}

(- 54)^{2} - 4 \cdot 3 \cdot 228 = 65

x_{1, 2} = \frac{- ( - 54 ) \pm 6 5}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 54 ) + 6 5}{2 \cdot 3}, x_{2} = \frac{- ( - 54 ) - 6 5}{2 \cdot 3}

x = \frac{- ( - 54 ) + 6 5}{2 \cdot 3} : 9 + 5

x = \frac{- ( - 54 ) - 6 5}{2 \cdot 3} : 9 - 5

The solutions to the quadratic equation are:

x = 9 + 5, x = 9 - 5

y, 2 x y^{2} - 3 x^{2} y = 6 x

8 x - 2 x^{2} = 1

x^{2} + 25 = 0

3 (x - 7)^{2} + 16 = 46

x^{2} - 4 x + 20

What are the solutions to the equation 3x^2+228=54x ?
The solutions to the equation 3x^2+228=54x are x=9+sqrt(5),x=9-sqrt(5)
Find the zeros of 3x^2+228=54x
The zeros of 3x^2+228=54x are x=9+sqrt(5),x=9-sqrt(5)