What are the solutions to the equation -3x^2+4x-9=2x^2+3 ?

The solutions to the equation -3x^2+4x-9=2x^2+3 are x= 2/5-i(2sqrt(14))/5 ,x= 2/5+i(2sqrt(14))/5

Find the zeros of -3x^2+4x-9=2x^2+3

The zeros of -3x^2+4x-9=2x^2+3 are x= 2/5-i(2sqrt(14))/5 ,x= 2/5+i(2sqrt(14))/5

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- 3 x^{2} + 4 x - 9 = 2 x^{2} + 3

x = \frac{2}{5} - i \frac{2 14}{5}, x = \frac{2}{5} + i \frac{2 14}{5}

Solution steps

- 3 x^{2} + 4 x - 9 = 2 x^{2} + 3

Move

3

to the left side

- 3 x^{2} + 4 x - 12 = 2 x^{2}

Move

2 x^{2}

to the left side

- 5 x^{2} + 4 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 5 ) ( - 12 )}{2 ( - 5 )}

Simplify

4^{2} - 4 (- 5) (- 12) : 414 i

x_{1, 2} = \frac{- 4 \pm 4 14 i}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 4 + 4 14 i}{2 ( - 5 )}, x_{2} = \frac{- 4 - 4 14 i}{2 ( - 5 )}

x = \frac{- 4 + 4 14 i}{2 ( - 5 )} : \frac{2}{5} - i \frac{2 14}{5}

x = \frac{- 4 - 4 14 i}{2 ( - 5 )} : \frac{2}{5} + i \frac{2 14}{5}

The solutions to the quadratic equation are:

x = \frac{2}{5} - i \frac{2 14}{5}, x = \frac{2}{5} + i \frac{2 14}{5}

x^{2} - 9 x - 21 = 0

- 3 k^{2} = 162

- 2 x^{2} + 8 x = 10

(2 y)^{2} = 4 y

a^{2} - 2 a + 2 = 4

What are the solutions to the equation -3x^2+4x-9=2x^2+3 ?
The solutions to the equation -3x^2+4x-9=2x^2+3 are x= 2/5-i(2sqrt(14))/5 ,x= 2/5+i(2sqrt(14))/5
Find the zeros of -3x^2+4x-9=2x^2+3
The zeros of -3x^2+4x-9=2x^2+3 are x= 2/5-i(2sqrt(14))/5 ,x= 2/5+i(2sqrt(14))/5