What are the solutions to the equation 3x^2-14x+4=0 ?

The solutions to the equation 3x^2-14x+4=0 are x=(7+sqrt(37))/3 ,x=(7-sqrt(37))/3

Find the zeros of 3x^2-14x+4=0

The zeros of 3x^2-14x+4=0 are x=(7+sqrt(37))/3 ,x=(7-sqrt(37))/3

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3 x^{2} - 14 x + 4 = 0

x = \frac{7 + 37}{3}, x = \frac{7 - 37}{3}

Decimal Notation

x = 4.36092 \dots, x = 0.30574 \dots

Solution steps

3 x^{2} - 14 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 3 \cdot 4}{2 \cdot 3}

(- 14)^{2} - 4 \cdot 3 \cdot 4 = 237

x_{1, 2} = \frac{- ( - 14 ) \pm 2 37}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 2 37}{2 \cdot 3}, x_{2} = \frac{- ( - 14 ) - 2 37}{2 \cdot 3}

x = \frac{- ( - 14 ) + 2 37}{2 \cdot 3} : \frac{7 + 37}{3}

x = \frac{- ( - 14 ) - 2 37}{2 \cdot 3} : \frac{7 - 37}{3}

The solutions to the quadratic equation are:

x = \frac{7 + 37}{3}, x = \frac{7 - 37}{3}

x, (x - h)^{2} + (y - k)^{2} = r^{2}

2 (x + 2)^{2} - 41 = - 9

X^{2} - 4 X - 1 = 0

3 x^{2} - 41 x + 26 = 0

x^{2} + 8 x - 20 = 0

What are the solutions to the equation 3x^2-14x+4=0 ?
The solutions to the equation 3x^2-14x+4=0 are x=(7+sqrt(37))/3 ,x=(7-sqrt(37))/3
Find the zeros of 3x^2-14x+4=0
The zeros of 3x^2-14x+4=0 are x=(7+sqrt(37))/3 ,x=(7-sqrt(37))/3