What are the solutions to the equation 0=-2(x-1)^2+5 ?

The solutions to the equation 0=-2(x-1)^2+5 are x=sqrt(5/2)+1,x=-sqrt(5/2)+1

Find the zeros of 0=-2(x-1)^2+5

The zeros of 0=-2(x-1)^2+5 are x=sqrt(5/2)+1,x=-sqrt(5/2)+1

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0 = - 2 (x - 1)^{2} + 5

x = \frac{5}{2} + 1, x = - \frac{5}{2} + 1

Decimal Notation

x = 2.58113 \dots, x = - 0.58113 \dots

Solution steps

0 = - 2 (x - 1)^{2} + 5

Switch sides

- 2 (x - 1)^{2} + 5 = 0

Move

5

to the right side

- 2 (x - 1)^{2} = - 5

Divide both sides by

- 2

(x - 1)^{2} = \frac{5}{2}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 1 = \frac{5}{2} : x = \frac{5}{2} + 1

Solve

x - 1 = - \frac{5}{2} : x = - \frac{5}{2} + 1

The solutions to the quadratic equation are:

x = \frac{5}{2} + 1, x = - \frac{5}{2} + 1

x^{2} - 20 x = - 5 x - 13 - x^{2}

5 c^{2} - 21 c + 11 = - 4 c

100 = - 1500 + 12 x - 0.004 x^{2}

- 2 p^{2} + 13 p - 12 = - 6 p^{2}

4 x^{2} = 76

What are the solutions to the equation 0=-2(x-1)^2+5 ?
The solutions to the equation 0=-2(x-1)^2+5 are x=sqrt(5/2)+1,x=-sqrt(5/2)+1
Find the zeros of 0=-2(x-1)^2+5
The zeros of 0=-2(x-1)^2+5 are x=sqrt(5/2)+1,x=-sqrt(5/2)+1