What are the solutions to the equation roots 3x^2-4x+2 ?

The solutions to the equation roots 3x^2-4x+2 are x= 2/3+i(sqrt(2))/3 ,x= 2/3-i(sqrt(2))/3

Find the zeros of roots 3x^2-4x+2

The zeros of roots 3x^2-4x+2 are x= 2/3+i(sqrt(2))/3 ,x= 2/3-i(sqrt(2))/3

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roots

3 x^{2} - 4 x + 2

x = \frac{2}{3} + i \frac{2}{3}, x = \frac{2}{3} - i \frac{2}{3}

Solution steps

3 x^{2} - 4 x + 2

The roots are the intercepts with the x-axis

(y = 0)

3 x^{2} - 4 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 3 \cdot 2}{2 \cdot 3}

Simplify

(- 4)^{2} - 4 \cdot 3 \cdot 2 : 22 i

x_{1, 2} = \frac{- ( - 4 ) \pm 2 2 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 2 i}{2 \cdot 3}, x_{2} = \frac{- ( - 4 ) - 2 2 i}{2 \cdot 3}

x = \frac{- ( - 4 ) + 2 2 i}{2 \cdot 3} : \frac{2}{3} + i \frac{2}{3}

x = \frac{- ( - 4 ) - 2 2 i}{2 \cdot 3} : \frac{2}{3} - i \frac{2}{3}

The solutions to the quadratic equation are:

x = \frac{2}{3} + i \frac{2}{3}, x = \frac{2}{3} - i \frac{2}{3}

x^{2} + x - 2 = 0

3 r^{2} - 8 r - 9 = 0

2 x^{2} + 3 x + 1 = 0

3 (x^{2} - 7) + 4 = 4

25 t^{2} - 40 t + 16 = 0

What are the solutions to the equation roots 3x^2-4x+2 ?
The solutions to the equation roots 3x^2-4x+2 are x= 2/3+i(sqrt(2))/3 ,x= 2/3-i(sqrt(2))/3
Find the zeros of roots 3x^2-4x+2
The zeros of roots 3x^2-4x+2 are x= 2/3+i(sqrt(2))/3 ,x= 2/3-i(sqrt(2))/3