What are the solutions to the equation roots x^2+2x-2 ?

The solutions to the equation roots x^2+2x-2 are x=-1+sqrt(3),x=-1-sqrt(3)

Find the zeros of roots x^2+2x-2

The zeros of roots x^2+2x-2 are x=-1+sqrt(3),x=-1-sqrt(3)

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roots

x^{2} + 2 x - 2

x = - 1 + 3, x = - 1 - 3

Solution steps

x^{2} + 2 x - 2

The roots are the intercepts with the x-axis

(y = 0)

x^{2} + 2 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 2) = 23

x_{1, 2} = \frac{- 2 \pm 2 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 3}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 3}{2 \cdot 1}

x = \frac{- 2 + 2 3}{2 \cdot 1} : - 1 + 3

x = \frac{- 2 - 2 3}{2 \cdot 1} : - 1 - 3

The solutions to the quadratic equation are:

x = - 1 + 3, x = - 1 - 3

6 w^{2} - 7 w - 3 = 0

2 w^{2} - 12 w + 18 = 0

x^{2} + 8 x + 15 = 0

y, x^{2} + y^{2} + 1 = 0

3 x^{2} + 2 x + 1

What are the solutions to the equation roots x^2+2x-2 ?
The solutions to the equation roots x^2+2x-2 are x=-1+sqrt(3),x=-1-sqrt(3)
Find the zeros of roots x^2+2x-2
The zeros of roots x^2+2x-2 are x=-1+sqrt(3),x=-1-sqrt(3)