What are the solutions to the equation 12x^2-32=0 ?

The solutions to the equation 12x^2-32=0 are x=(2sqrt(2))/(sqrt(3)),x=-(2sqrt(2))/(sqrt(3))

Find the zeros of 12x^2-32=0

The zeros of 12x^2-32=0 are x=(2sqrt(2))/(sqrt(3)),x=-(2sqrt(2))/(sqrt(3))

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12 x^{2} - 32 = 0

x = \frac{2 2}{3}, x = - \frac{2 2}{3}

Decimal Notation

x = 1.63299 \dots, x = - 1.63299 \dots

Solution steps

12 x^{2} - 32 = 0

Move

32

to the right side

12 x^{2} = 32

Divide both sides by

12

x^{2} = \frac{8}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{8}{3}, x = - \frac{8}{3}

\frac{8}{3} = \frac{2 2}{3}

- \frac{8}{3} = - \frac{2 2}{3}

x = \frac{2 2}{3}, x = - \frac{2 2}{3}

- 5 x^{2} + x = 0

x, z = 9 - x^{2} - y^{2}

x^{2} - 3 x + 2 = 0

3 q^{2} + 5 q - 8 = 0

f, f^{- 1} (x) = x^{2}

What are the solutions to the equation 12x^2-32=0 ?
The solutions to the equation 12x^2-32=0 are x=(2sqrt(2))/(sqrt(3)),x=-(2sqrt(2))/(sqrt(3))
Find the zeros of 12x^2-32=0
The zeros of 12x^2-32=0 are x=(2sqrt(2))/(sqrt(3)),x=-(2sqrt(2))/(sqrt(3))