What are the solutions to the equation x^2-61x+900=0 ?

The solutions to the equation x^2-61x+900=0 are x=36,x=25

Find the zeros of x^2-61x+900=0

The zeros of x^2-61x+900=0 are x=36,x=25

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x^{2} - 61 x + 900 = 0

x = 36, x = 25

Solution steps

x^{2} - 61 x + 900 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 61 ) \pm ( - 61 ) ^{2} - 4 \cdot 1 \cdot 900}{2 \cdot 1}

(- 61)^{2} - 4 \cdot 1 \cdot 900 = 11

x_{1, 2} = \frac{- ( - 61 ) \pm 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 61 ) + 11}{2 \cdot 1}, x_{2} = \frac{- ( - 61 ) - 11}{2 \cdot 1}

x = \frac{- ( - 61 ) + 11}{2 \cdot 1} : 36

x = \frac{- ( - 61 ) - 11}{2 \cdot 1} : 25

The solutions to the quadratic equation are:

x = 36, x = 25

- 2 x^{2} - 3 = 8 x + 6

- 3 x^{2} - 4 x + 2

4 x^{2} + 9 x - 7 = 2

9 x^{2} - 6 x = 8

3 v^{2} + 63 v - 66 = 0

What are the solutions to the equation x^2-61x+900=0 ?
The solutions to the equation x^2-61x+900=0 are x=36,x=25
Find the zeros of x^2-61x+900=0
The zeros of x^2-61x+900=0 are x=36,x=25