What are the solutions to the equation 6x=2x^2-7x+14 ?

The solutions to the equation 6x=2x^2-7x+14 are x=(13+sqrt(57))/4 ,x=(13-sqrt(57))/4

Find the zeros of 6x=2x^2-7x+14

The zeros of 6x=2x^2-7x+14 are x=(13+sqrt(57))/4 ,x=(13-sqrt(57))/4

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6 x = 2 x^{2} - 7 x + 14

x = \frac{13 + 57}{4}, x = \frac{13 - 57}{4}

Decimal Notation

x = 5.13745 \dots, x = 1.36254 \dots

Solution steps

6 x = 2 x^{2} - 7 x + 14

Switch sides

2 x^{2} - 7 x + 14 = 6 x

Move

6 x

to the left side

2 x^{2} - 13 x + 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 2 \cdot 14}{2 \cdot 2}

(- 13)^{2} - 4 \cdot 2 \cdot 14 = 57

x_{1, 2} = \frac{- ( - 13 ) \pm 57}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 13 ) + 57}{2 \cdot 2}, x_{2} = \frac{- ( - 13 ) - 57}{2 \cdot 2}

x = \frac{- ( - 13 ) + 57}{2 \cdot 2} : \frac{13 + 57}{4}

x = \frac{- ( - 13 ) - 57}{2 \cdot 2} : \frac{13 - 57}{4}

The solutions to the quadratic equation are:

x = \frac{13 + 57}{4}, x = \frac{13 - 57}{4}

x, x y^{4} + x^{2} y = x + 3 y

x^{2} + 29.4 x - 756.3 = 0

30 x^{2} - 9 x - 12 = 0

x, x^{2} + p x + q = 0

x^{2} - x - 72 = 0

What are the solutions to the equation 6x=2x^2-7x+14 ?
The solutions to the equation 6x=2x^2-7x+14 are x=(13+sqrt(57))/4 ,x=(13-sqrt(57))/4
Find the zeros of 6x=2x^2-7x+14
The zeros of 6x=2x^2-7x+14 are x=(13+sqrt(57))/4 ,x=(13-sqrt(57))/4