What are the solutions to the equation roots x^2-2x+c ?

The solutions to the equation roots x^2-2x+c are x=1+sqrt(-c+1),x=1-sqrt(-c+1)

Find the zeros of roots x^2-2x+c

The zeros of roots x^2-2x+c are x=1+sqrt(-c+1),x=1-sqrt(-c+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

roots

x^{2} - 2 x + c

x = 1 + - c + 1, x = 1 - - c + 1

Solution steps

x^{2} - 2 x + c

The roots are the intercepts with the x-axis

(y = 0)

x^{2} - 2 x + c = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot c}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot c : 2 1 - c

x_{1, 2} = \frac{- ( - 2 ) \pm 2 1 - c}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 1 - c}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 1 - c}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 1 - c}{2 \cdot 1} : 1 + - c + 1

x = \frac{- ( - 2 ) - 2 1 - c}{2 \cdot 1} : 1 - - c + 1

The solutions to the quadratic equation are:

x = 1 + - c + 1, x = 1 - - c + 1

x^{2} - 18 x + 145 = 0

4 z^{2} - 4 z - 15 = 0

4.9 x^{2} + 340 x - 1700 = 0

y, x^{2} + y^{2} - 4 x + 10 y + 29 = 0

5 (x^{2} - 8) - 5 = 5

What are the solutions to the equation roots x^2-2x+c ?
The solutions to the equation roots x^2-2x+c are x=1+sqrt(-c+1),x=1-sqrt(-c+1)
Find the zeros of roots x^2-2x+c
The zeros of roots x^2-2x+c are x=1+sqrt(-c+1),x=1-sqrt(-c+1)