What are the solutions to the equation 10x^2+6x-30=0 ?

The solutions to the equation 10x^2+6x-30=0 are x=(-3+sqrt(309))/(10),x=-(3+sqrt(309))/(10)

Find the zeros of 10x^2+6x-30=0

The zeros of 10x^2+6x-30=0 are x=(-3+sqrt(309))/(10),x=-(3+sqrt(309))/(10)

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10 x^{2} + 6 x - 30 = 0

x = \frac{- 3 + 309}{10}, x = - \frac{3 + 309}{10}

Decimal Notation

x = 1.45783 \dots, x = - 2.05783 \dots

Solution steps

10 x^{2} + 6 x - 30 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 10 ( - 30 )}{2 \cdot 10}

6^{2} - 4 \cdot 10 (- 30) = 2309

x_{1, 2} = \frac{- 6 \pm 2 309}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 6 + 2 309}{2 \cdot 10}, x_{2} = \frac{- 6 - 2 309}{2 \cdot 10}

x = \frac{- 6 + 2 309}{2 \cdot 10} : \frac{- 3 + 309}{10}

x = \frac{- 6 - 2 309}{2 \cdot 10} : - \frac{3 + 309}{10}

The solutions to the quadratic equation are:

x = \frac{- 3 + 309}{10}, x = - \frac{3 + 309}{10}

4 x^{2} - 8 x = - 3

x, cy (x)^{2} = x^{2} + y

x^{2} + 4 = 3 x

x^{2} - 7 = 2

(2 x - 1)^{2} = x

What are the solutions to the equation 10x^2+6x-30=0 ?
The solutions to the equation 10x^2+6x-30=0 are x=(-3+sqrt(309))/(10),x=-(3+sqrt(309))/(10)
Find the zeros of 10x^2+6x-30=0
The zeros of 10x^2+6x-30=0 are x=(-3+sqrt(309))/(10),x=-(3+sqrt(309))/(10)