What are the solutions to the equation 0=2(x+1)^2+3 ?

The solutions to the equation 0=2(x+1)^2+3 are x=isqrt(3/2)-1,x=-isqrt(3/2)-1

Find the zeros of 0=2(x+1)^2+3

The zeros of 0=2(x+1)^2+3 are x=isqrt(3/2)-1,x=-isqrt(3/2)-1

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0 = 2 (x + 1)^{2} + 3

x = i \frac{3}{2} - 1, x = - i \frac{3}{2} - 1

Solution steps

0 = 2 (x + 1)^{2} + 3

Switch sides

2 (x + 1)^{2} + 3 = 0

Move

3

to the right side

2 (x + 1)^{2} = - 3

Divide both sides by

2

(x + 1)^{2} = - \frac{3}{2}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = - \frac{3}{2} : x = i \frac{3}{2} - 1

Solve

x + 1 = - - \frac{3}{2} : x = - i \frac{3}{2} - 1

The solutions to the quadratic equation are:

x = i \frac{3}{2} - 1, x = - i \frac{3}{2} - 1

y, x^{2} + 2 x y - y^{2} + x = 2

x^{2} + 7 x = 0

4 x^{2} - 11 = 12 x

3 x^{2} - 7 x - 22 = 0

x^{2} + 6 x + 1 = - 2 x + 1

What are the solutions to the equation 0=2(x+1)^2+3 ?
The solutions to the equation 0=2(x+1)^2+3 are x=isqrt(3/2)-1,x=-isqrt(3/2)-1
Find the zeros of 0=2(x+1)^2+3
The zeros of 0=2(x+1)^2+3 are x=isqrt(3/2)-1,x=-isqrt(3/2)-1