What are the solutions to the equation 2(3x+2)^2=26 ?

The solutions to the equation 2(3x+2)^2=26 are x=(sqrt(13)-2)/3 ,x=(-sqrt(13)-2)/3

Find the zeros of 2(3x+2)^2=26

The zeros of 2(3x+2)^2=26 are x=(sqrt(13)-2)/3 ,x=(-sqrt(13)-2)/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 (3 x + 2)^{2} = 26

x = \frac{13 - 2}{3}, x = \frac{- 13 - 2}{3}

Decimal Notation

x = 0.53518 \dots, x = - 1.86851 \dots

Solution steps

2 (3 x + 2)^{2} = 26

Divide both sides by

2

(3 x + 2)^{2} = 13

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x + 2 = 13 : x = \frac{13 - 2}{3}

Solve

3 x + 2 = - 13 : x = \frac{- 13 - 2}{3}

The solutions to the quadratic equation are:

x = \frac{13 - 2}{3}, x = \frac{- 13 - 2}{3}

- 4 = x^{2} + 14 x + 49

3 x^{2} - 11 x - 20 = 0

p^{2} + (p + 7)^{2} = 169

4 n^{2} + 23 n + 16 = 1

- 1 L^{2} + 41.5 L = 0

What are the solutions to the equation 2(3x+2)^2=26 ?
The solutions to the equation 2(3x+2)^2=26 are x=(sqrt(13)-2)/3 ,x=(-sqrt(13)-2)/3
Find the zeros of 2(3x+2)^2=26
The zeros of 2(3x+2)^2=26 are x=(sqrt(13)-2)/3 ,x=(-sqrt(13)-2)/3