What are the solutions to the equation roots x^2+10x+100 ?

The solutions to the equation roots x^2+10x+100 are x=-5+5sqrt(3)i,x=-5-5sqrt(3)i

Find the zeros of roots x^2+10x+100

The zeros of roots x^2+10x+100 are x=-5+5sqrt(3)i,x=-5-5sqrt(3)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

roots

x^{2} + 10 x + 100

x = - 5 + 53 i, x = - 5 - 53 i

Solution steps

x^{2} + 10 x + 100

The roots are the intercepts with the x-axis

(y = 0)

x^{2} + 10 x + 100 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 100}{2 \cdot 1}

Simplify

1 0^{2} - 4 \cdot 1 \cdot 100 : 103 i

x_{1, 2} = \frac{- 10 \pm 10 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 10 3 i}{2 \cdot 1}, x_{2} = \frac{- 10 - 10 3 i}{2 \cdot 1}

x = \frac{- 10 + 10 3 i}{2 \cdot 1} : - 5 + 53 i

x = \frac{- 10 - 10 3 i}{2 \cdot 1} : - 5 - 53 i

The solutions to the quadratic equation are:

x = - 5 + 53 i, x = - 5 - 53 i

y^{2} - 8 y - 2 = 0

x, x^{2} - 3 y^{2} - 2 y + z^{2} - 4 z = - 5

2 c^{2} - 5 c - 14 = - 5

x^{2} - 6 x + 8 = 0

5 r^{2} + r - 2 = 0

What are the solutions to the equation roots x^2+10x+100 ?
The solutions to the equation roots x^2+10x+100 are x=-5+5sqrt(3)i,x=-5-5sqrt(3)i
Find the zeros of roots x^2+10x+100
The zeros of roots x^2+10x+100 are x=-5+5sqrt(3)i,x=-5-5sqrt(3)i