What are the solutions to the equation -7x^2-10=-12x ?

The solutions to the equation -7x^2-10=-12x are x= 6/7-i(sqrt(34))/7 ,x= 6/7+i(sqrt(34))/7

Find the zeros of -7x^2-10=-12x

The zeros of -7x^2-10=-12x are x= 6/7-i(sqrt(34))/7 ,x= 6/7+i(sqrt(34))/7

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- 7 x^{2} - 10 = - 12 x

x = \frac{6}{7} - i \frac{34}{7}, x = \frac{6}{7} + i \frac{34}{7}

Solution steps

- 7 x^{2} - 10 = - 12 x

Move

12 x

to the left side

- 7 x^{2} - 10 + 12 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- 7 x^{2} + 12 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 ( - 7 ) ( - 10 )}{2 ( - 7 )}

Simplify

1 2^{2} - 4 (- 7) (- 10) : 234 i

x_{1, 2} = \frac{- 12 \pm 2 34 i}{2 ( - 7 )}

Separate the solutions

x_{1} = \frac{- 12 + 2 34 i}{2 ( - 7 )}, x_{2} = \frac{- 12 - 2 34 i}{2 ( - 7 )}

x = \frac{- 12 + 2 34 i}{2 ( - 7 )} : \frac{6}{7} - i \frac{34}{7}

x = \frac{- 12 - 2 34 i}{2 ( - 7 )} : \frac{6}{7} + i \frac{34}{7}

The solutions to the quadratic equation are:

x = \frac{6}{7} - i \frac{34}{7}, x = \frac{6}{7} + i \frac{34}{7}

x, 7 x^{2} - 5 x y + y^{3} = 3

x^{2} + 10 x + 29

x^{2} - 11 x - 46 = - 6 x + 4

y, x^{2} + x y = ln (y)

4 x^{2} - 16 x + 20 = 0

What are the solutions to the equation -7x^2-10=-12x ?
The solutions to the equation -7x^2-10=-12x are x= 6/7-i(sqrt(34))/7 ,x= 6/7+i(sqrt(34))/7
Find the zeros of -7x^2-10=-12x
The zeros of -7x^2-10=-12x are x= 6/7-i(sqrt(34))/7 ,x= 6/7+i(sqrt(34))/7