What are the solutions to the equation 2(x-5)^2+2=20 ?

The solutions to the equation 2(x-5)^2+2=20 are x=8,x=2

Find the zeros of 2(x-5)^2+2=20

The zeros of 2(x-5)^2+2=20 are x=8,x=2

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2 (x - 5)^{2} + 2 = 20

x = 8, x = 2

Solution steps

2 (x - 5)^{2} + 2 = 20

Move

2

to the right side

2 (x - 5)^{2} = 18

Divide both sides by

2

(x - 5)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 5 = 9 : x = 8

Solve

x - 5 = - 9 : x = 2

The solutions to the quadratic equation are:

x = 8, x = 2

8 x^{2} = 72 x

(3 x - 2)^{2} = (x + 1)^{2}

y, x^{2} - 14 x y + y^{2} = 14

2 x^{2} + 12 x + 6

x, x^{2} + 20 x + 900 I (x) = 180 x

What are the solutions to the equation 2(x-5)^2+2=20 ?
The solutions to the equation 2(x-5)^2+2=20 are x=8,x=2
Find the zeros of 2(x-5)^2+2=20
The zeros of 2(x-5)^2+2=20 are x=8,x=2