What are the solutions to the equation factor x^2-4x-12=0 ?

The solutions to the equation factor x^2-4x-12=0 are x=-2,x=6

Find the zeros of factor x^2-4x-12=0

The zeros of factor x^2-4x-12=0 are x=-2,x=6

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x^{2} - 4 x - 12 = 0

x = - 2, x = 6

Solution steps

x^{2} - 4 x - 12 = 0

Factor

x^{2} - 4 x - 12 : (x + 2) (x - 6)

(x + 2) (x - 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x - 6 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x - 6 = 0 : x = 6

The solutions to the quadratic equation are:

x = - 2, x = 6

- 2 (x + 9) (x - 1)

2 a^{2} - a - 11 = - 3

2 x^{2} + 82 = - 24 x

y, x^{2} + x = y^{2} + y

3 x^{2} + 7 x + 4 = 0

What are the solutions to the equation factor x^2-4x-12=0 ?
The solutions to the equation factor x^2-4x-12=0 are x=-2,x=6
Find the zeros of factor x^2-4x-12=0
The zeros of factor x^2-4x-12=0 are x=-2,x=6