What are the solutions to the equation 4t^2+4t+1=0 ?

The solutions to the equation 4t^2+4t+1=0 are t=-1/2

Find the zeros of 4t^2+4t+1=0

The zeros of 4t^2+4t+1=0 are t=-1/2

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4 t^{2} + 4 t + 1 = 0

t = - \frac{1}{2}

Decimal Notation

t = - 0.5

Solution steps

4 t^{2} + 4 t + 1 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

4^{2} - 4 \cdot 4 \cdot 1 = 0

t_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 4}

t = \frac{- 4}{2 \cdot 4}

\frac{- 4}{2 \cdot 4} = - \frac{1}{2}

t = - \frac{1}{2}

The solution to the quadratic equation is:

t = - \frac{1}{2}

8 t^{2} - 26 t + 15 = 0

- 3 x^{2} + 2 = - (2 x - 1)^{2}

100 + 9 x^{2} = 11 x^{2} + 50

x^{2} + 8 x + 4 = 0

x^{2} - 18 x = - 79

What are the solutions to the equation 4t^2+4t+1=0 ?
The solutions to the equation 4t^2+4t+1=0 are t=-1/2
Find the zeros of 4t^2+4t+1=0
The zeros of 4t^2+4t+1=0 are t=-1/2