What is (2k^3-7k^2+3k)-(-4k^2+5k) ?

The solution to (2k^3-7k^2+3k)-(-4k^2+5k) is 2k^3-3k^2-2k

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simplify (2k^3-7k^2+3k)-(-4k^2+5k)

simplify

(2 k^{3} - 7 k^{2} + 3 k) - (- 4 k^{2} + 5 k)

2 k^{3} - 3 k^{2} - 2 k

Solution steps

(2 k^{3} - 7 k^{2} + 3 k) - (- 4 k^{2} + 5 k)

Apply rule:

(a) = a

(2 k^{3} - 7 k^{2} + 3 k) = 2 k^{3} - 7 k^{2} + 3 k

= 2 k^{3} - 7 k^{2} + 3 k - (- 4 k^{2} + 5 k)

Apply the distributive law:

- (- a + b) = a - b

- (- 4 k^{2} + 5 k) = 4 k^{2} - 5 k

= 2 k^{3} - 7 k^{2} + 3 k + 4 k^{2} - 5 k

Group like terms

= 2 k^{3} - 7 k^{2} + 4 k^{2} + 3 k - 5 k

Add similar elements:

- 7 k^{2} + 4 k^{2} = - 3 k^{2}

= 2 k^{3} - 3 k^{2} + 3 k - 5 k

Add similar elements:

3 k - 5 k = - 2 k

= 2 k^{3} - 3 k^{2} - 2 k

p^{2} + 12 p + 36

- 3 + \frac{1}{3} x = - 8

9 c - 1 < 4 c - 5

t^{3} - 5 t^{2} + 10 - 2 t

3 x + 7 = 12 - 2 x

What is (2k^3-7k^2+3k)-(-4k^2+5k) ?
The solution to (2k^3-7k^2+3k)-(-4k^2+5k) is 2k^3-3k^2-2k