What are the solutions to the equation solvefor y,x^2-xy+y^2=0 ?

The solutions to the equation solvefor y,x^2-xy+y^2=0 are y= x/2+i(sqrt(3)x)/2 ,y= x/2-i(sqrt(3)x)/2

Find the zeros of solvefor y,x^2-xy+y^2=0

The zeros of solvefor y,x^2-xy+y^2=0 are y= x/2+i(sqrt(3)x)/2 ,y= x/2-i(sqrt(3)x)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solve for

y, x^{2} - x y + y^{2} = 0

y = \frac{x}{2} + i \frac{3 x}{2}, y = \frac{x}{2} - i \frac{3 x}{2}

Solution steps

x^{2} - x y + y^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

y^{2} - x y + x^{2} = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - x ) \pm ( - x ) ^{2} - 4 \cdot 1 \cdot x ^{2}}{2 \cdot 1}

Simplify

(- x)^{2} - 4 \cdot 1 \cdot x^{2} : 3 i x

y_{1, 2} = \frac{- ( - x ) \pm 3 i x}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - x ) + 3 i x}{2 \cdot 1}, y_{2} = \frac{- ( - x ) - 3 i x}{2 \cdot 1}

y = \frac{- ( - x ) + 3 i x}{2 \cdot 1} : \frac{x}{2} + i \frac{3 x}{2}

y = \frac{- ( - x ) - 3 i x}{2 \cdot 1} : \frac{x}{2} - i \frac{3 x}{2}

The solutions to the quadratic equation are:

y = \frac{x}{2} + i \frac{3 x}{2}, y = \frac{x}{2} - i \frac{3 x}{2}

y, 3 x^{2} + 2 x y + y^{2} = 2

x, c x^{2} + x + y^{2} = 0

4 x^{2} + 85 = - 36 x

- 2 x^{2} + 5 x - 6 = 0

x^{2} - 8 x + c

What are the solutions to the equation solvefor y,x^2-xy+y^2=0 ?
The solutions to the equation solvefor y,x^2-xy+y^2=0 are y= x/2+i(sqrt(3)x)/2 ,y= x/2-i(sqrt(3)x)/2
Find the zeros of solvefor y,x^2-xy+y^2=0
The zeros of solvefor y,x^2-xy+y^2=0 are y= x/2+i(sqrt(3)x)/2 ,y= x/2-i(sqrt(3)x)/2