What are the solutions to the equation 2x^2-19x-10=0 ?

The solutions to the equation 2x^2-19x-10=0 are x=10,x=-1/2

Find the zeros of 2x^2-19x-10=0

The zeros of 2x^2-19x-10=0 are x=10,x=-1/2

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2 x^{2} - 19 x - 10 = 0

x = 10, x = - \frac{1}{2}

Decimal Notation

x = 10, x = - 0.5

Solution steps

2 x^{2} - 19 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 19 ) \pm ( - 19 ) ^{2} - 4 \cdot 2 ( - 10 )}{2 \cdot 2}

(- 19)^{2} - 4 \cdot 2 (- 10) = 21

x_{1, 2} = \frac{- ( - 19 ) \pm 21}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 19 ) + 21}{2 \cdot 2}, x_{2} = \frac{- ( - 19 ) - 21}{2 \cdot 2}

x = \frac{- ( - 19 ) + 21}{2 \cdot 2} : 10

x = \frac{- ( - 19 ) - 21}{2 \cdot 2} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = 10, x = - \frac{1}{2}

2 x^{2} + x - 3

x^{2} - 4 x = 77

4 x^{2} - 11 = 4 x

x^{2} - 2 x - 15

x^{2} - 3 x + 1

What are the solutions to the equation 2x^2-19x-10=0 ?
The solutions to the equation 2x^2-19x-10=0 are x=10,x=-1/2
Find the zeros of 2x^2-19x-10=0
The zeros of 2x^2-19x-10=0 are x=10,x=-1/2