What are the solutions to the equation solvefor y,x^2+y^2+72=12x ?

The solutions to the equation solvefor y,x^2+y^2+72=12x are y=sqrt(12x-x^2-72),y=-sqrt(12x-x^2-72)

Find the zeros of solvefor y,x^2+y^2+72=12x

The zeros of solvefor y,x^2+y^2+72=12x are y=sqrt(12x-x^2-72),y=-sqrt(12x-x^2-72)

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solve for

y, x^{2} + y^{2} + 72 = 12 x

y = 12 x - x^{2} - 72, y = - 12 x - x^{2} - 72

Solution steps

x^{2} + y^{2} + 72 = 12 x

Move

x^{2}

to the right side

y^{2} + 72 = 12 x - x^{2}

Move

72

to the right side

y^{2} = 12 x - x^{2} - 72

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = 12 x - x^{2} - 72, y = - 12 x - x^{2} - 72

5 c^{2} + 12 c + 4 = 0

3 v^{2} - v - 12 = - 6

x^{2} - 16 x = - 73

2 x^{2} - 3 x = - x^{2} + 3

30 x^{2} - 5 x = 0

What are the solutions to the equation solvefor y,x^2+y^2+72=12x ?
The solutions to the equation solvefor y,x^2+y^2+72=12x are y=sqrt(12x-x^2-72),y=-sqrt(12x-x^2-72)
Find the zeros of solvefor y,x^2+y^2+72=12x
The zeros of solvefor y,x^2+y^2+72=12x are y=sqrt(12x-x^2-72),y=-sqrt(12x-x^2-72)