What are the solutions to the equation 96=80x-16x^2 ?

The solutions to the equation 96=80x-16x^2 are x=2,x=3

Find the zeros of 96=80x-16x^2

The zeros of 96=80x-16x^2 are x=2,x=3

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96 = 80 x - 16 x^{2}

x = 2, x = 3

Solution steps

96 = 80 x - 16 x^{2}

Switch sides

80 x - 16 x^{2} = 96

Move

96

to the left side

80 x - 16 x^{2} - 96 = 0

Write in the standard form

a x^{2} + b x + c = 0

- 16 x^{2} + 80 x - 96 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 80 \pm 8 0 ^{2} - 4 ( - 16 ) ( - 96 )}{2 ( - 16 )}

8 0^{2} - 4 (- 16) (- 96) = 16

x_{1, 2} = \frac{- 80 \pm 16}{2 ( - 16 )}

Separate the solutions

x_{1} = \frac{- 80 + 16}{2 ( - 16 )}, x_{2} = \frac{- 80 - 16}{2 ( - 16 )}

x = \frac{- 80 + 16}{2 ( - 16 )} : 2

x = \frac{- 80 - 16}{2 ( - 16 )} : 3

The solutions to the quadratic equation are:

x = 2, x = 3

x^{2} + 53 = 14 x

200 = - 0.5 x^{2} + 30 x - 200

4 (5 x - 7)^{2} - 40 = - 32

3 (2 x + 5)^{2} + 23 = 38

y, x^{2} y^{2} + x y = 6

What are the solutions to the equation 96=80x-16x^2 ?
The solutions to the equation 96=80x-16x^2 are x=2,x=3
Find the zeros of 96=80x-16x^2
The zeros of 96=80x-16x^2 are x=2,x=3