What are the solutions to the equation 2W^2+W-45=0 ?

The solutions to the equation 2W^2+W-45=0 are W= 9/2 ,W=-5

Find the zeros of 2W^2+W-45=0

The zeros of 2W^2+W-45=0 are W= 9/2 ,W=-5

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2 W^{2} + W - 45 = 0

W = \frac{9}{2}, W = - 5

Decimal Notation

W = 4.5, W = - 5

Solution steps

2 W^{2} + W - 45 = 0

Solve with the quadratic formula

W_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 2 ( - 45 )}{2 \cdot 2}

1^{2} - 4 \cdot 2 (- 45) = 19

W_{1, 2} = \frac{- 1 \pm 19}{2 \cdot 2}

Separate the solutions

W_{1} = \frac{- 1 + 19}{2 \cdot 2}, W_{2} = \frac{- 1 - 19}{2 \cdot 2}

W = \frac{- 1 + 19}{2 \cdot 2} : \frac{9}{2}

W = \frac{- 1 - 19}{2 \cdot 2} : - 5

The solutions to the quadratic equation are:

W = \frac{9}{2}, W = - 5

3 x^{2} + 5 x = 1428

x^{2} - 2 = 2 x - 2

x, z = y^{2} - x^{2}

25 x^{2} - \frac{4}{49} = 0

2 x^{2} - 16 x = - 22

What are the solutions to the equation 2W^2+W-45=0 ?
The solutions to the equation 2W^2+W-45=0 are W= 9/2 ,W=-5
Find the zeros of 2W^2+W-45=0
The zeros of 2W^2+W-45=0 are W= 9/2 ,W=-5