What are the solutions to the equation r^2-r+1/4 =0 ?

The solutions to the equation r^2-r+1/4 =0 are r= 1/2

Find the zeros of r^2-r+1/4 =0

The zeros of r^2-r+1/4 =0 are r= 1/2

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r^{2} - r + \frac{1}{4} = 0

r = \frac{1}{2}

Decimal Notation

r = 0.5

Solution steps

r^{2} - r + \frac{1}{4} = 0

Multiply both sides by

4

4 r^{2} - 4 r + 1 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

(- 4)^{2} - 4 \cdot 4 \cdot 1 = 0

r_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 \cdot 4}

r = \frac{- ( - 4 )}{2 \cdot 4}

\frac{- ( - 4 )}{2 \cdot 4} = \frac{1}{2}

r = \frac{1}{2}

The solution to the quadratic equation is:

r = \frac{1}{2}

2 x^{2} = - 144

x^{2} + 2 x - 8

x^{2} + 2 x - 3

x^{2} - 14 x + 196 = 0

- 2 x^{2} - 4 x + 7

What are the solutions to the equation r^2-r+1/4 =0 ?
The solutions to the equation r^2-r+1/4 =0 are r= 1/2
Find the zeros of r^2-r+1/4 =0
The zeros of r^2-r+1/4 =0 are r= 1/2