What are the solutions to the equation roots x^2+6x+9 ?

The solutions to the equation roots x^2+6x+9 are x=-3

Find the zeros of roots x^2+6x+9

The zeros of roots x^2+6x+9 are x=-3

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roots

x^{2} + 6 x + 9

x = - 3

Solution steps

x^{2} + 6 x + 9

The roots are the intercepts with the x-axis

(y = 0)

x^{2} + 6 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 9 = 0

x_{1, 2} = \frac{- 6 \pm 0}{2 \cdot 1}

x = \frac{- 6}{2 \cdot 1}

\frac{- 6}{2 \cdot 1} = - 3

x = - 3

The solution to the quadratic equation is:

x = - 3

- 3 x^{2} = 21

4 x^{2} + 12 x = - 5

x^{2} - 11 x = - 30

4 x^{2} + 1.2 x = 0

x^{2} + 15 x + 50

What are the solutions to the equation roots x^2+6x+9 ?
The solutions to the equation roots x^2+6x+9 are x=-3
Find the zeros of roots x^2+6x+9
The zeros of roots x^2+6x+9 are x=-3