What are the solutions to the equation 25(x^2-1)+13=-8 ?

The solutions to the equation 25(x^2-1)+13=-8 are x= 2/5 ,x=-2/5

Find the zeros of 25(x^2-1)+13=-8

The zeros of 25(x^2-1)+13=-8 are x= 2/5 ,x=-2/5

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25 (x^{2} - 1) + 13 = - 8

x = \frac{2}{5}, x = - \frac{2}{5}

Decimal Notation

x = 0.4, x = - 0.4

Solution steps

25 (x^{2} - 1) + 13 = - 8

Move

13

to the right side

25 (x^{2} - 1) = - 21

Divide both sides by

25

x^{2} - 1 = - \frac{21}{25}

Move

1

to the right side

x^{2} = \frac{4}{25}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{4}{25}, x = - \frac{4}{25}

\frac{4}{25} = \frac{2}{5}

- \frac{4}{25} = - \frac{2}{5}

x = \frac{2}{5}, x = - \frac{2}{5}

x^{2} - 14 x + 49 = 0

2 x^{2} + 18 = 4 x

4 x^{2} - 23 x + 28 = 0

- 70 p^{2} + 240 p + 366 = 0

x, - 7 s in x + 3 x^{2} = - \frac{1}{3}

What are the solutions to the equation 25(x^2-1)+13=-8 ?
The solutions to the equation 25(x^2-1)+13=-8 are x= 2/5 ,x=-2/5
Find the zeros of 25(x^2-1)+13=-8
The zeros of 25(x^2-1)+13=-8 are x= 2/5 ,x=-2/5