What are the solutions to the equation 6x^2-72x+192=0 ?

The solutions to the equation 6x^2-72x+192=0 are x=8,x=4

Find the zeros of 6x^2-72x+192=0

The zeros of 6x^2-72x+192=0 are x=8,x=4

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6 x^{2} - 72 x + 192 = 0

x = 8, x = 4

Solution steps

6 x^{2} - 72 x + 192 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 72 ) \pm ( - 72 ) ^{2} - 4 \cdot 6 \cdot 192}{2 \cdot 6}

(- 72)^{2} - 4 \cdot 6 \cdot 192 = 24

x_{1, 2} = \frac{- ( - 72 ) \pm 24}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 72 ) + 24}{2 \cdot 6}, x_{2} = \frac{- ( - 72 ) - 24}{2 \cdot 6}

x = \frac{- ( - 72 ) + 24}{2 \cdot 6} : 8

x = \frac{- ( - 72 ) - 24}{2 \cdot 6} : 4

The solutions to the quadratic equation are:

x = 8, x = 4

16 x - 8 = 9 x^{2} - 9 x - 108

4 d^{2} + 2 d - 2 = 3 d

81 x^{2} + 198 x + 121 = 0

v, F = \frac{m v ^{2}}{r ^{2}}

3 + x = x^{2} + 3 x

What are the solutions to the equation 6x^2-72x+192=0 ?
The solutions to the equation 6x^2-72x+192=0 are x=8,x=4
Find the zeros of 6x^2-72x+192=0
The zeros of 6x^2-72x+192=0 are x=8,x=4