What are the solutions to the equation k^2+4k+4=0 ?

The solutions to the equation k^2+4k+4=0 are k=-2

Find the zeros of k^2+4k+4=0

The zeros of k^2+4k+4=0 are k=-2

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k^{2} + 4 k + 4 = 0

k = - 2

Solution steps

k^{2} + 4 k + 4 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 4 = 0

k_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 1}

k = \frac{- 4}{2 \cdot 1}

\frac{- 4}{2 \cdot 1} = - 2

k = - 2

The solution to the quadratic equation is:

k = - 2

4 x^{2} + x - 33

\frac{4 - 2}{2}

\frac{81}{64}

(x + 5)^{3} - (2 x + 1)^{3}

3^{2} + 6^{2}

What are the solutions to the equation k^2+4k+4=0 ?
The solutions to the equation k^2+4k+4=0 are k=-2
Find the zeros of k^2+4k+4=0
The zeros of k^2+4k+4=0 are k=-2