What are the solutions to the equation x^2-31=2x ?

The solutions to the equation x^2-31=2x are x=1+4sqrt(2),x=1-4sqrt(2)

Find the zeros of x^2-31=2x

The zeros of x^2-31=2x are x=1+4sqrt(2),x=1-4sqrt(2)

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x^{2} - 31 = 2 x

x = 1 + 42, x = 1 - 42

Decimal Notation

x = 6.65685 \dots, x = - 4.65685 \dots

Solution steps

x^{2} - 31 = 2 x

Move

2 x

to the left side

x^{2} - 31 - 2 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 2 x - 31 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 31 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 31) = 82

x_{1, 2} = \frac{- ( - 2 ) \pm 8 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 8 2}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 8 2}{2 \cdot 1}

x = \frac{- ( - 2 ) + 8 2}{2 \cdot 1} : 1 + 42

x = \frac{- ( - 2 ) - 8 2}{2 \cdot 1} : 1 - 42

The solutions to the quadratic equation are:

x = 1 + 42, x = 1 - 42

2 x^{2} + 6 x - 7 = 2

x, 3 x^{2} + 30 x - 5 = 0

5 r^{2} + 24 r - 3 = 2

m, x^{2} + m (x)^{2} x (m (x) - 2) = 2 m (x)^{5}

9 (2 - x) = 2 x^{2}

What are the solutions to the equation x^2-31=2x ?
The solutions to the equation x^2-31=2x are x=1+4sqrt(2),x=1-4sqrt(2)
Find the zeros of x^2-31=2x
The zeros of x^2-31=2x are x=1+4sqrt(2),x=1-4sqrt(2)